Python Leap Year Determination
Python3 ExamplesThe following example is used to determine whether the year entered by the user is a leap year:
Example (Python 3.0+)
# -*- coding: UTF-8 -*-
# Filename : test.py
# author by : www.example.com
year = int(input("Enter a year:"))
if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
print("{0} is a leap year".format(year)) # Century years divisible by 400 are leap years
else:
print("{0} is not a leap year".format(year))
else:
print("{0} is a leap year".format(year)) # Non-century years divisible by 4 are leap years
else:
print("{0} is not a leap year".format(year))
We can also use nested if statements to implement it:
The output after executing the above code is:
输入一个年份: 2000 2000 是闰年
输入一个年份: 2011 2011 不是闰年Other Extensions