Python Simple Calculator Implementation
The following code is used to implement a simple calculator, including basic addition, subtraction, multiplication, and division operations for two numbers:
Example (Python 3.0+)
# Filename : test.py
# author by : www.example.com
# Define functions
def add(x, y):
"""Addition"""
return x + y
def subtract(x, y):
"""Subtraction"""
return x - y
def multiply(x, y):
"""Multiplication"""
return x * y
def divide(x, y):
"""Division"""
return x / y
# User input
print("Select operation:")
print("1. Addition")
print("2. Subtraction")
print("3. Multiplication")
print("4. Division")
choice = input("Enter your choice (1/2/3/4):")
num1 = int(input("Enter the first number:"))
num2 = int(input("Enter the second number:"))
if choice == '1':
print(num1,"+",num2,"=", add(num1,num2))
elif choice == '2':
print(num1,"-",num2,"=", subtract(num1,num2))
elif choice == '3':
print(num1,"*",num2,"=", multiply(num1,num2))
elif choice == '4':
print(num1,"/",num2,"=", divide(num1,num2))
else:
print("Invalid input")
The output of the above code is:
选择运算: 1、相加 2、相减 3、相乘 4、相除 输入你的选择(1/2/3/4):2 输入第一个数字: 5 输入第二个数字: 2 5 - 2 = 3
Another implementation code:
Example
# Simple calculator program
# Define function to perform addition
def add(x, y):
return x + y
# Define function to perform subtraction
def subtract(x, y):
return x - y
# Define function to perform multiplication
def multiply(x, y):
return x * y
# Define function to perform division
def divide(x, y):
if y != 0:
return x / y
else:
return "Cannot divide by zero"
# Main program loop
while True:
print("\nChoose an operation:")
print("1. Addition")
print("2. Subtraction")
print("3. Multiplication")
print("4. Division")
print("5. Exit")
choice = input("Enter option number: ")
if choice in ('1', '2', '3', '4'):
num1 = float(input("Enter the first number: "))
num2 = float(input("Enter the second number: "))
if choice == '1':
print(f"Result: {add(num1, num2)}")
elif choice == '2':
print(f"Result: {subtract(num1, num2)}")
elif choice == '3':
print(f"Result: {multiply(num1, num2)}")
elif choice == '4':
print(f"Result: {divide(num1, num2)}")
elif choice == '5':
print("Exiting program.")
break
else:
print("Invalid option, please try again.")
# Define function to perform addition
def add(x, y):
return x + y
# Define function to perform subtraction
def subtract(x, y):
return x - y
# Define function to perform multiplication
def multiply(x, y):
return x * y
# Define function to perform division
def divide(x, y):
if y != 0:
return x / y
else:
return "Cannot divide by zero"
# Main program loop
while True:
print("\nChoose an operation:")
print("1. Addition")
print("2. Subtraction")
print("3. Multiplication")
print("4. Division")
print("5. Exit")
choice = input("Enter option number: ")
if choice in ('1', '2', '3', '4'):
num1 = float(input("Enter the first number: "))
num2 = float(input("Enter the second number: "))
if choice == '1':
print(f"Result: {add(num1, num2)}")
elif choice == '2':
print(f"Result: {subtract(num1, num2)}")
elif choice == '3':
print(f"Result: {multiply(num1, num2)}")
elif choice == '4':
print(f"Result: {divide(num1, num2)}")
elif choice == '5':
print("Exiting program.")
break
else:
print("Invalid option, please try again.")
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