Python Practice Example 29

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Problem:Given a positive integer with no more than 5 digits, the requirements are: First, find how many digits it has; second, print each digit in reverse order.

Program analysis:Learn to decompose each digit.

Program source code:

Example (Python 2.x)

#!/usr/bin/python # -*- coding: UTF-8 -*- x = int(raw_input("Please enter a number:\n")) a = x / 10000 b = x % 10000 / 1000 c = x % 1000 / 100 d = x % 100 / 10 e = x % 10 if a != 0: print "5 digits:",e,d,c,b,a elif b != 0: print "4 digits:",e,d,c,b, elif c != 0: print "3 digits:",e,d,c elif d != 0: print "2 digits:",e,d else: print "1 digit:",e

Example (Python 3.x)

#!/usr/bin/python x = int(input("Please enter a number:\n")) a = x // 10000 b = x % 10000 // 1000 c = x % 1000 // 100 d = x % 100 // 10 e = x % 10 if a != 0: print ("5 digits:",e,d,c,b,a) elif b != 0: print ("4 digits:",e,d,c,b) elif c != 0: print ("3 digits:",e,d,c) elif d != 0: print ("2 digits:",e,d) else: print ("1 digit:",e)

The output result of the above example is:

请输入一个数:
23459
5 位数: 9 5 4 3 2
请输入一个数:
3472
4 位数: 2 7 4 3

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