PHP date_sub()Functions
PHP Date/Time Reference Manual
Examples
Subtract 40 days from March 15, 2013:
<?php
$date=date_create("2013-03-15");
date_sub($date,date_interval_create_from_date_string("40 days"));
echo date_format($date,"Y-m-d");
?>
$date=date_create("2013-03-15");
date_sub($date,date_interval_create_from_date_string("40 days"));
echo date_format($date,"Y-m-d");
?>
Run Example »
Definition and Usage
The date_sub() function subtracts days, months, years, hours, minutes, and seconds from a specified date.
Syntax
date_sub(object,interval);
| Parameters | Description |
|---|---|
| object | Required. Specifies adate_create()returned DateTime object. |
| interval | Required. Specifies a DateInterval object. |
Technical Details
| Return value: | Returns a DateTime object on success, or FALSE on failure. |
|---|---|
| PHP Version: | 5.3+ |
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