Magic Square Description:
- A magic square is an N*N matrix;
- The sum of each row, each column, and the diagonals of this matrix are all equal;
Magic square example:
3rd-order magic square:
8 1 6 3 5 7 4 9 2
Sum of each row:
8+1+6=15;
3+5+7=15;
4+9+2=15;
Sum of each column:
8+3+4=15;
1+5+9=15;
6+7+2=15;
Sum of diagonals:
8+5+2=15;
6+5+4=15;
Magic square calculation rules (rows and columns start at 1):
1. Place "1" in the first row, middle column;
2. Starting from 2 to N*N, each number follows this rule: the row where each number is stored is the previous number's row minus 1; the column where each number is stored is the previous number's column plus 1;
3. When a number's row is 1, the next number's row is N;
4. When a number's column is N, the next number's column is 1, and the row number decreases by 1;
5. If the position determined by the above rules already has a number, or the previous number is at the 1st row and Nth column,
the next number is placed directly below the previous number (i.e., row number decreases by 1, column unchanged);
Source Code
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define N 5
int main()
{
int a[N][N] = {0};
int count = 1;
int row = 0, cul = N / 2;
while (count <= N*N)
{
a[row][cul] = count;
int i = row;
int j = cul;
if (i == 0)
{
i = N - 1;
}
else
{
i = i - 1;
}
j = (j + 1) % N;
if (a[i][j]!=0||(row==0&&cul==N-1))
{
i = row + 1;
j = cul;
}
row = i;
cul = j;
count++;
}
for (int i = 0; i < N; i++)
{
for (int j = 0; j < N; j++)
{
printf("%3d",a[i][j]);
}
printf("\n");
}
system("pause");
}
The output of the above code is:
17 24 1 8 15 23 5 7 14 16 4 6 13 20 22 10 12 19 21 3 11 18 25 2 9