C Exercise Example 8

100 Classic C Examples

Title:Output9*9Mnemonic.

Program analysis:Consider rows and columns, there are 9 rows and 9 columns, i controls rows, j controls columns.

Program source code:

Example

// Created by www.example.com on 15/11/9. // Copyright © 2015 Example. All rights reserved. // #include <stdio.h> int main() { int i, j, result; printf("\n"); for (i = 1; i < 10; i++) { for (j = 1; j <= i; j++) { result = i * j; printf("%d*%d=%-3d", i, j, result); /*-3d means left-aligned, occupying 3 positions*/ } printf("\n"); /*Newline after each line*/ } return 0; }

Detailed explanation of the code:

  • for (i = 1; i < 10; i++): The outer loop iterates the multiplicand (i) from 1 to 9.
  • for (j = 1; j <= i; j++): The inner loop iterates the multiplier (j) from 1 to i.
  • result = i * j;: Calculate the result of multiplication.
  • printf("%d*%d=%-3d", i, j, result);: Print the multiplication expression and result in a left-aligned format occupying 3 positions.
  • printf("\n");: After each inner loop ends, print a newline to move to the next row to process the next multiplicand.

The output result of the above example is:

1*1=1  
2*1=2  2*2=4  
3*1=3  3*2=6  3*3=9  
4*1=4  4*2=8  4*3=12 4*4=16 
5*1=5  5*2=10 5*3=15 5*4=20 5*5=25 
6*1=6  6*2=12 6*3=18 6*4=24 6*5=30 6*6=36 
7*1=7  7*2=14 7*3=21 7*4=28 7*5=35 7*6=42 7*7=49 
8*1=8  8*2=16 8*3=24 8*4=32 8*5=40 8*6=48 8*7=56 8*8=64 
9*1=9  9*2=18 9*3=27 9*4=36 9*5=45 9*6=54 9*7=63 9*8=72 9*9=81 

100 Classic C Examples

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