C Language Example - Counting Various Characters in a String
Count the vowels, consonants, digits, and whitespace characters in a string.
Example
#include <stdio.h>
int main()
{
char line[150];
int i, vowels, consonants, digits, spaces;
vowels = consonants = digits = spaces = 0;
printf("Enter a string:");
scanf("%[^\n]", line);
for(i=0; line[i]!='\0'; ++i)
{
if(line[i]=='a' || line[i]=='e' || line[i]=='i' ||
line[i]=='o' || line[i]=='u' || line[i]=='A' ||
line[i]=='E' || line[i]=='I' || line[i]=='O' ||
line[i]=='U')
{
++vowels;
}
else if((line[i]>='a'&& line[i]<='z') || (line[i]>='A'&& line[i]<='Z'))
{
++consonants;
}
else if(line[i]>='0' && line[i]<='9')
{
++digits;
}
else if (line[i]==' ')
{
++spaces;
}
}
printf("Vowels: %d",vowels);
printf("\nConsonants: %d",consonants);
printf("\nDigits: %d",digits);
printf("\nWhitespace: %d", spaces);
return 0;
}
The output is:
输入一个字符串: example123 erkcomsww dfexample 元音: 8 辅音: 15 数字: 3 空白符: 2other extensions