C Language Example - Finding the Least Common Multiple of Two Numbers
The user inputs two numbers, and the least common multiple of these two numbers is calculated.
Example - Using while and if
#include <stdio.h>
int main()
{
int n1, n2, minMultiple;
printf("Enter two positive integers:");
scanf("%d %d", &n1, &n2);
// Determine the larger value of the two numbers and assign it to minMultiple
minMultiple = (n1>n2) ? n1 : n2;
// The condition is true
while(1)
{
if( minMultiple%n1==0 && minMultiple%n2==0 )
{
printf("The least common multiple of %d and %d is %d", n1, n2,minMultiple);
break;
}
++minMultiple;
}
return 0;
}
Run result:
输入两个正整数: 72 120 72 和 120 的最小公倍数为 360
Example - Calculating via Greatest Common Divisor
#include <stdio.h>
int main()
{
int n1, n2, i, gcd, lcm;
printf("Enter two positive integers:");
scanf("%d %d",&n1,&n2);
for(i=1; i <= n1 && i <= n2; ++i)
{
// Determine the greatest common divisor
if(n1%i==0 && n2%i==0)
gcd = i;
}
lcm = (n1*n2)/gcd;
printf("The least common multiple of %d and %d is %d", n1, n2, lcm);
return 0;
}
Run result:
输入两个正整数: 72 120 72 和 120 的最小公倍数为 360other extensions